Solve the problem. Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$, as needed.
-Find the $\mathrm{pH}$ if $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=3.6 \times 10^{-14}$.
A) 13.7
B) -14.6
C) 14.6
D) 13.4

Question

Quizplus · Accepted Answer

The Answer of Solve the problem. Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$, as needed.
-Find the $\mathrm{pH}$ if $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=3.6 \times 10^{-14}$.
A) 13.7
B) -14.6
C) 14.6
D) 13.4

Solve the Problem pH=−log⁡[H3O+]\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]pH=−log[H3​O+] , as Needed pH\mathrm{pH}pH If [H3O+]=3.6×10−14\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=3.6 \times 10^{-14}[H3​O+]=3.6×10−14

Solve the Problem $\mathrm{pH}=-\log \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$ , as Needed $\mathrm{pH}$ If $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=3.6 \times 10^{-14}$