A boy is standing on a flat field and tosses his ball toward a second boy standing at the other end of the field. The path of the ball is a parabola, and the equation of the path is $f(x)=-4 x^{2}+8 x$. Based on this information, answer the question.
-How many $x$-intercepts are there on the graph of the equation?
A) 1
B) 2
C) 0
D) None of the above

Question

Quizplus · Accepted Answer

To find the $x$-intercepts, we set $f(x) = 0$. So, $0 = -4x^2 + 8x$. Factoring out $4x$, we get $4x(-x + 2) = 0$. This gives us two solutions for $x$, $x = 0$ and $x = 2$, indicating there are 2 $x$-intercepts.

A Boy Is Standing on a Flat Field and Tosses f(x)=−4x2+8xf(x)=-4 x^{2}+8 xf(x)=−4x2+8x

A Boy Is Standing on a Flat Field and Tosses $f(x)=-4 x^{2}+8 x$