Solve the equation.
-$25 x^{4}-61 x^{2}+36=0$

A) $\left\{-\frac{6}{5},-1,1, \frac{6}{5}\right\}$

B) $\left\{-1,-\frac{5}{6}, \frac{5}{6}, 1\right\}$

C) $\left\{1, \frac{6}{5}\right\}$

D) $\left\{-1,-\frac{5}{6}\right\}$

Question

Solve the equation.
-$25 x^{4}-61 x^{2}+36=0$

A) $\left\{-\frac{6}{5},-1,1, \frac{6}{5}\right\}$

B) $\left\{-1,-\frac{5}{6}, \frac{5}{6}, 1\right\}$

C) $\left\{1, \frac{6}{5}\right\}$

D) $\left\{-1,-\frac{5}{6}\right\}$

Quizplus · Accepted Answer

This equation can be solved by substituting $y = x^2$, turning it into a quadratic equation $25y^2 - 61y + 36 = 0$. Solving this quadratic equation gives $y = \frac{36}{25}$ and $y = 1$. Substituting back $x^2 = y$ gives the solutions for $x$ as $\pm\frac{6}{5}$ and $\pm1$.

Solve the Equation 25x4−61x2+36=025 x^{4}-61 x^{2}+36=025x4−61x2+36=0 A) {−65,−1,1,65}\left\{-\frac{6}{5},-1,1, \frac{6}{5}\right\}{−56​,−1,1,56​} B) {−1,−56,56,1}\left\{-1,-\frac{5}{6}, \frac{5}{6}, 1\right\}{−1,−65​,65​,1}

Solve the Equation $25 x^{4}-61 x^{2}+36=0$ A) $\left\{-\frac{6}{5},-1,1, \frac{6}{5}\right\}$ B) $\left\{-1,-\frac{5}{6}, \frac{5}{6}, 1\right\}$