Solve the formula for the indicated variable.
-$T=2 \pi \sqrt{\frac{L}{K}}$ for $L$

A) $\mathrm{L}=\frac{\mathrm{KT}^{2}}{2 \pi}$

B) $\mathrm{L}=\frac{\mathrm{K}^{2} \mathrm{~T}^{2}}{4 \pi^{2}}$

C) $\mathrm{L}=\frac{\mathrm{KT}}{2 \pi}$

D) $\mathrm{L}=\frac{\mathrm{KT}^{2}}{4 \pi^{2}}$

Question

Solve the formula for the indicated variable.
-$T=2 \pi \sqrt{\frac{L}{K}}$ for $L$

A) $\mathrm{L}=\frac{\mathrm{KT}^{2}}{2 \pi}$

B) $\mathrm{L}=\frac{\mathrm{K}^{2} \mathrm{~T}^{2}}{4 \pi^{2}}$

C) $\mathrm{L}=\frac{\mathrm{KT}}{2 \pi}$

D) $\mathrm{L}=\frac{\mathrm{KT}^{2}}{4 \pi^{2}}$

Quizplus · Accepted Answer

To solve for $L$, square both sides of the equation to get rid of the square root, resulting in $T^2 = 4\pi^2 \frac{L}{K}$. Then, solve for $L$ by multiplying both sides by $K$ and dividing by $4\pi^2$, which gives $L = \frac{KT^2}{4\pi^2}$.

Solve the Formula for the Indicated Variable T=2πLKT=2 \pi \sqrt{\frac{L}{K}}T=2πKL​​ For LLL

Solve the Formula for the Indicated Variable $T=2 \pi \sqrt{\frac{L}{K}}$ For $L$