Solve the problem. Give the answer as a simplified radical expression.
-Find the perimeter of a lot with sides measuring $5 \sqrt{50}, 2 \sqrt{18}, 3 \sqrt{8}$, and $2 \sqrt{12}$ yards.
A) $37+4 \sqrt{3}$ yards
B) $41 \sqrt{2}$ yards
C) $74+4 \sqrt{3}$ yards
D) $37 \sqrt{2}+4 \sqrt{3}$ yards

Question

Quizplus · Accepted Answer

First, simplify each term: $5\sqrt{50} = 5\sqrt{25}\sqrt{2} = 25\sqrt{2}$, $2\sqrt{18} = 2\sqrt{9}\sqrt{2} = 6\sqrt{2}$, $3\sqrt{8} = 3\sqrt{4}\sqrt{2} = 6\sqrt{2}$, $2\sqrt{12} = 2\sqrt{4}\sqrt{3} = 4\sqrt{3}$. Adding these gives $25\sqrt{2} + 6\sqrt{2} + 6\sqrt{2} + 4\sqrt{3} = 37\sqrt{2} + 4\sqrt{3}$ yards.

Solve the Problem 550,218,385 \sqrt{50}, 2 \sqrt{18}, 3 \sqrt{8}550​,218​,38​ , And 2122 \sqrt{12}212​

Solve the Problem $5 \sqrt{50}, 2 \sqrt{18}, 3 \sqrt{8}$ , And $2 \sqrt{12}$