Find the equation of a circle satisfying the given conditions.
-Center: $(0,4)$; radius: 6
A) $x^{2}+(y-4)^{2}=36$
B) $(x+4)^{2}+y^{2}=36$
C) $(x-4)^{2}+y^{2}=36$
D) $x^{2}+(y+4)^{2}=6$

Question

Quizplus · Accepted Answer

The general equation of a circle with center $(h, k)$ and radius $r$ is $(x-h)^{2} + (y-k)^{2} = r^{2}$. For a center at $(0,4)$ and radius $6$, the equation is $x^{2}+(y-4)^{2}=36$.

Find the Equation of a Circle Satisfying the Given Conditions (0,4)(0,4)(0,4)

Find the Equation of a Circle Satisfying the Given Conditions $(0,4)$