If an object is projected upward with an initial velocity of $96 \mathrm{ft}$ per sec from a height $\mathrm{h}$ of $256 \mathrm{ft}$, then its height $t$ sec after it is projected is defined by the equation $h=-16 t^{2}+96 t+256$. How many sec after it is projected will it hit the ground?
A) $10 \mathrm{sec}$
B) $8 \mathrm{sec}$
C) $2 \mathrm{sec}$
D) $9 \mathrm{sec}$

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h = 0$ and solve $-16t^2 + 96t + 256 = 0$. Solving this quadratic equation gives $t = 8$ seconds.

If an Object Is Projected Upward with an Initial Velocity 96ft96 \mathrm{ft}96ft

If an Object Is Projected Upward with an Initial Velocity $96 \mathrm{ft}$