Solve the equation
-$(3 \mathrm{x}-1)^{2}=25 \mathrm{x}^{2}$

A) $\left\{-\frac{1}{2}, \frac{1}{8}\right\}$

B) $\left\{-\frac{2}{5},-\frac{5}{2}\right\}$

C) $\left\{\frac{1}{3},-\frac{1}{3}\right\}$

D) $\left\{-\frac{1}{2}\right\}$

Question

Solve the equation
-$(3 \mathrm{x}-1)^{2}=25 \mathrm{x}^{2}$

A) $\left\{-\frac{1}{2}, \frac{1}{8}\right\}$

B) $\left\{-\frac{2}{5},-\frac{5}{2}\right\}$

C) $\left\{\frac{1}{3},-\frac{1}{3}\right\}$

D) $\left\{-\frac{1}{2}\right\}$

Quizplus · Accepted Answer

Expanding $(3x-1)^2$ gives $9x^2 - 6x + 1 = 25x^2$. Rearranging gives $16x^2 - 6x - 1 = 0$. Solving this quadratic equation yields $x = -\frac{1}{2}$ and $x = \frac{1}{8}$.