Factor the polynomial completely
-$9 y^{2}+18 y+8$
A) $(9 y+2)(y+4)$
B) $(3 y+2)(3 y+4)$
C) $(9 y+1)(y-8)$
D) $(3 y-2)(3 y-4)$

Question

Quizplus · Accepted Answer

The polynomial $9y^2 + 18y + 8$ can be factored by looking for two numbers that multiply to $9*8 = 72$ and add to $18$. These numbers are $12$ and $6$, so the polynomial can be rewritten as $9y^2 + 12y + 6y + 8$. Factoring by grouping, we get $3y(3y+4) + 2(3y+4)$, which simplifies to $(3y+2)(3y+4)$.

Factor the Polynomial Completely - 9y2+18y+89 y^{2}+18 y+89y2+18y+8 A) (9y+2)(y+4)(9 y+2)(y+4)(9y+2)(y+4) B) (3y+2)(3y+4)(3 y+2)(3 y+4)(3y+2)(3y+4)

Factor the Polynomial Completely
- $9 y^{2}+18 y+8$ A) $(9 y+2)(y+4)$ B) $(3 y+2)(3 y+4)$