Factor the polynomial completely
-$50 a^{4}-98 b^{2}$
A) $2\left(5 a^{2}-7 b\right)^{2}$
B) $2\left(5 a^{2}+7 b\right)\left(5 a^{2}-7 b\right)$
C) $2\left(5 a^{2}+7 b\right)^{2}$
D) $\left(10 a^{2}+14 b\right)\left(5 a^{2}-7 b\right)$

Question

Quizplus · Accepted Answer

The polynomial $50a^4 - 98b^2$ can be factored as $2(25a^4 - 49b^2)$, which is a difference of squares. It further factors into $2(5a^2)^2 - (7b)^2$, leading to $2(5a^2 + 7b)(5a^2 - 7b)$.

Factor the Polynomial Completely - 50a4−98b250 a^{4}-98 b^{2}50a4−98b2 A) 2(5a2−7b)22\left(5 a^{2}-7 b\right)^{2}2(5a2−7b)2

Factor the Polynomial Completely
- $50 a^{4}-98 b^{2}$ A) $2\left(5 a^{2}-7 b\right)^{2}$