Find the product
-$(\mathrm{p}+6)^{2}$

A) $p^{2}+36$
B) $p+36$
C) $p^{2}+12 p+36$
D) $36 p^{2}+12 p+36$

Name: Find the product -$(\mathrm{p}+6)^{2}$ A) $p^{2}+36$ B) $p+36$ C) $p^{2}+12 p+36$ D) $36 p^{2}+12 p+36$
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Question

Find the product
-$(\mathrm{p}+6)^{2}$

A) $p^{2}+36$
B) $p+36$
C) $p^{2}+12 p+36$
D) $36 p^{2}+12 p+36$

Quizplus · Accepted Answer

To find the product $(\mathrm{p}+6)^{2}$, we use the formula $(a+b)^{2} = a^{2} + 2ab + b^{2}$. Applying this to $(\mathrm{p}+6)^{2}$, we get $p^{2} + 2 \cdot p \cdot 6 + 6^{2} = p^{2} + 12p + 36$.

Find the Product - (p+6)2(\mathrm{p}+6)^{2}(p+6)2 A) p2+36p^{2}+36p2+36 B) p+36p+36p+36 C) p2+12p+36p^{2}+12 p+36p2+12p+36 D) 36p2+12p+3636 p^{2}+12 p+3636p2+12p+36

Find the Product
- $(\mathrm{p}+6)^{2}$ A) $p^{2}+36$ B) $p+36$ C) $p^{2}+12 p+36$ D) $36 p^{2}+12 p+36$