Find the product
-$(3 \mathrm{p}+11)(3 \mathrm{p}-11)$

A) $9 p^{2}-66 p-121$
B) $9 p^{2}+66 p-121$
C) $p^{2}-121$
D) $9 p^{2}-121$

Name: Find the product -$(3 \mathrm{p}+11)(3 \mathrm{p}-11)$ A) $9 p^{2}-66 p-121$ B) $9 p^{2}+66 p-121$ C) $p^{2}-121$ D) $9 p^{2}-121$
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Question

Find the product
-$(3 \mathrm{p}+11)(3 \mathrm{p}-11)$

A) $9 p^{2}-66 p-121$
B) $9 p^{2}+66 p-121$
C) $p^{2}-121$
D) $9 p^{2}-121$

Quizplus · Accepted Answer

This is a difference of squares problem, where the formula is $a^2 - b^2 = (a+b)(a-b)$. Applying this to the given expression, $a = 3p$ and $b = 11$, so the product is $(3p)^2 - (11)^2 = 9p^2 - 121$.

Find the Product - (3p+11)(3p−11)(3 \mathrm{p}+11)(3 \mathrm{p}-11)(3p+11)(3p−11) A) 9p2−66p−1219 p^{2}-66 p-1219p2−66p−121 B) 9p2+66p−1219 p^{2}+66 p-1219p2+66p−121

Find the Product
- $(3 \mathrm{p}+11)(3 \mathrm{p}-11)$ A) $9 p^{2}-66 p-121$ B) $9 p^{2}+66 p-121$