Find the product
-$-8 a x^{7}\left(9 a x^{6}-12 x^{2}-8 a\right)$

A) $-72 a^{2} x^{42}+96 a x^{14}+64 a^{2} x^{7}$
B) $-72 a^{2} x^{13}+96 a x^{9}+64 a^{2} x^{7}$
C) $-72 a x^{13}+96 a x^{9}+64 a x^{7}$
D) $-72 a^{2} x^{13}-96 a x^{9}-64 a^{2} x^{7}$

Question

Find the product
-$-8 a x^{7}\left(9 a x^{6}-12 x^{2}-8 a\right)$

A) $-72 a^{2} x^{42}+96 a x^{14}+64 a^{2} x^{7}$
B) $-72 a^{2} x^{13}+96 a x^{9}+64 a^{2} x^{7}$
C) $-72 a x^{13}+96 a x^{9}+64 a x^{7}$
D) $-72 a^{2} x^{13}-96 a x^{9}-64 a^{2} x^{7}$

Quizplus · Accepted Answer

When multiplying $-8 a x^{7}$ by each term inside the parentheses, the exponents of $x$ are added and the coefficients are multiplied. For the first term, $-8 * 9 = -72$ and $a * a = a^{2}$, with $x^{7} * x^{6} = x^{13}$, resulting in $-72 a^{2} x^{13}$. For the second term, $-8 * -12 = 96$ and the exponent of $x$ becomes $7 + 2 = 9$, resulting in $96 a x^{9}$. For the third term, $-8 * -8 = 64$ and $a$ remains, with the exponent of $x$ staying at $7$, resulting in $64 a^{2} x^{7}$.

Find the Product - −8ax7(9ax6−12x2−8a)-8 a x^{7}\left(9 a x^{6}-12 x^{2}-8 a\right)−8ax7(9ax6−12x2−8a)

Find the Product
- $-8 a x^{7}\left(9 a x^{6}-12 x^{2}-8 a\right)$