The perimeter of a rectangle is $60 \mathrm{~m}$. If the width were doubled and the length were increased by 15 $\mathrm{m}$, the perimeter would be $108 \mathrm{~m}$. What are the length and width of the rectangle?
A) Length: $15 \mathrm{~m}$; width: $15 \mathrm{~m}$
B) Length: $15 \mathrm{~m}$; width: $10 \mathrm{~m}$
C) Length: $21 \mathrm{~m}$; width: $9 \mathrm{~m}$
D) Length: $9 \mathrm{~m}$; width: $21 \mathrm{~m}$

Question

Quizplus · Accepted Answer

Let the original length and width be $l$ and $w$, respectively.Then, $2(l+w)=60 \Rightarrow l+w=30$.Also, $2(2w+l+15)=108 \Rightarrow 2w+l=48$.Solving these two equations, we get $l=21$ and $w=9$.

The Perimeter of a Rectangle Is 60 m60 \mathrm{~m}60 m If the Width Were Doubled and the Length Were

The Perimeter of a Rectangle Is $60 \mathrm{~m}$ If the Width Were Doubled and the Length Were