Solve the equation.
-$x+\frac{3}{2}=12$
A) $x=\frac{21}{2}$
B) $x=9$
C) $x=\frac{27}{2}$
D) $x=\frac{9}{2}$

Name: Solve the equation. -$x+\frac{3}{2}=12$ A) $x=\frac{21}{2}$ B) $x=9$ C) $x=\frac{27}{2}$ D) $x=\frac{9}{2}$
Brand: Quizplus
Rating: 4.8 (36 reviews)

Question

Quizplus · Accepted Answer

To solve for $x$, subtract $\frac{3}{2}$ from both sides of the equation: $x = 12 - \frac{3}{2}$. Converting 12 to a fraction with a denominator of 2 gives $x = \frac{24}{2} - \frac{3}{2} = \frac{21}{2}$.

Solve the Equation x+32=12x+\frac{3}{2}=12x+23​=12 A) x=212x=\frac{21}{2}x=221​ B) x=9x=9x=9 C) x=272x=\frac{27}{2}x=227​ D) x=92x=\frac{9}{2}x=29​

Solve the Equation $x+\frac{3}{2}=12$ A) $x=\frac{21}{2}$ B) $x=9$ C) $x=\frac{27}{2}$ D) $x=\frac{9}{2}$