Solve the problem.
-In order for a chemical reaction to take place, the Fahrenheit temperature of the reagents must be at least $133.09^{\circ} \mathrm{F}$. Find the Celsius temperatures at which the reaction may occur. $\left(\mathrm{F}=\frac{9}{5} \mathrm{C}+32\right)$
A) $\mathrm{C} \geq 271.56^{\circ}$
B) $\mathrm{C} \leq 56.16^{\circ}$
C) $\mathrm{C} \geq 56.16^{\circ}$
D) $\mathrm{C}

Question

Solve the problem.
-In order for a chemical reaction to take place, the Fahrenheit temperature of the reagents must be at least $133.09^{\circ} \mathrm{F}$. Find the Celsius temperatures at which the reaction may occur. $\left(\mathrm{F}=\frac{9}{5} \mathrm{C}+32\right)$
A) $\mathrm{C} \geq 271.56^{\circ}$
B) $\mathrm{C} \leq 56.16^{\circ}$
C) $\mathrm{C} \geq 56.16^{\circ}$
D) $\mathrm{C}<271.56^{\circ}$

Quizplus · Accepted Answer

To convert $133.09^{\circ}F$ to Celsius, use the formula $C = \frac{5}{9}(F - 32)$. Substituting $133.09$ for $F$, we get $C = \frac{5}{9}(133.09 - 32) = \frac{5}{9}(101.09) = 56.16^{\circ}C$. Therefore, the reaction occurs at $C \geq 56.16^{\circ}C$.

Solve the Problem 133.09∘F133.09^{\circ} \mathrm{F}133.09∘F Find the Celsius Temperatures at Which the Reaction May

Solve the Problem $133.09^{\circ} \mathrm{F}$ Find the Celsius Temperatures at Which the Reaction May