Solve the problem.
-Find the length of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width. $(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})$
A) $20 \mathrm{~m}$
B) $40 \mathrm{~m}$
C) $35 \mathrm{~m}$
D) $15 \mathrm{~m}$

Question

Quizplus · Accepted Answer

Given the perimeter $P = 70$ meters and the length $L = W + 5$, the equation for the perimeter becomes $70 = 2(W + 5) + 2W$. Solving this equation for $W$ gives $W = 15$ meters, and thus $L = 20$ meters.

Solve the Problem (P=2 L+2 W)(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})(P=2 L+2 W) A) 20 m20 \mathrm{~m}20 m B) 40 m40 \mathrm{~m}40 m C) 35 m35 \mathrm{~m}35 m

Solve the Problem $(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})$ A) $20 \mathrm{~m}$ B) $40 \mathrm{~m}$ C) $35 \mathrm{~m}$