Solve the problem.
-A room measures $16 \mathrm{ft}$ by $21 \mathrm{ft}$. The ceiling is $10 \mathrm{ft}$ above the floor. There is one window measuring $3 \mathrm{ft}$ by $7 \mathrm{ft}$. The door is $3 \mathrm{ft}$ by $6 \frac{1}{2} \mathrm{ft}$. What is the total area of the walls and ceiling (excluding the door and window)?
A) $699.5 \mathrm{ft}^{2}$
B) $295.5 \mathrm{ft}^{2}$
C) $1035.5 \mathrm{ft}^{2}$
D) $665.5 \mathrm{ft}^{2}$

Question

Quizplus · Accepted Answer

The total area of the walls is calculated by finding the perimeter of the room and multiplying by the height, then adding the ceiling area and subtracting the areas of the window and door. The perimeter is $2(16 + 21) = 74 \mathrm{ft}$. The wall area is $74 \times 10 = 740 \mathrm{ft}^2$. The ceiling area is $16 \times 21 = 336 \mathrm{ft}^2$. The window area is $3 \times 7 = 21 \mathrm{ft}^2$ and the door area is $3 \times 6.5 = 19.5 \mathrm{ft}^2$. Total area = $740 + 336 - 21 - 19.5 = 1035.5 \mathrm{ft}^2$.

Solve the Problem 16ft16 \mathrm{ft}16ft By 21ft21 \mathrm{ft}21ft the Ceiling Is 10ft10 \mathrm{ft}10ft

Solve the Problem $16 \mathrm{ft}$ By $21 \mathrm{ft}$ the Ceiling Is $10 \mathrm{ft}$