Factor.
-$x^{3}-343$
A) $(x+343)\left(x^{2}-1\right)$
B) $(x-7)\left(x^{2}+7 x+49\right)$
C) $(x+7)\left(x^{2}-7 x+49\right)$
D) $(x-7)\left(x^{2}+49\right)$

Question

Quizplus · Accepted Answer

The expression $x^{3}-343$ is a difference of cubes, which can be factored as $(a-b)(a^{2}+ab+b^{2})$, where $a=x$ and $b=7$. Therefore, the correct factorization is $(x-7)(x^{2}+7x+49)$.

Factor - x3−343x^{3}-343x3−343 A) (x+343)(x2−1)(x+343)\left(x^{2}-1\right)(x+343)(x2−1) B) (x−7)(x2+7x+49)(x-7)\left(x^{2}+7 x+49\right)(x−7)(x2+7x+49) C) (x+7)(x2−7x+49)(x+7)\left(x^{2}-7 x+49\right)(x+7)(x2−7x+49) D) (x−7)(x2+49)(x-7)\left(x^{2}+49\right)(x−7)(x2+49)

Factor
- $x^{3}-343$ A) $(x+343)\left(x^{2}-1\right)$ B) $(x-7)\left(x^{2}+7 x+49\right)$ C) $(x+7)\left(x^{2}-7 x+49\right)$ D) $(x-7)\left(x^{2}+49\right)$