Simplify.
-$\frac{\frac{1}{a}+1}{\frac{1}{a}-1}$
A) $1-a^{2}$
B) 1
C) $\frac{a}{1-a^{2}}$
D) $\frac{1+a}{1-a}$

Question

Quizplus · Accepted Answer

To simplify the given expression, $\frac{\frac{1}{a}+1}{\frac{1}{a}-1}$, we first find a common denominator for the numerator and the denominator, which is $a$. This gives us $\frac{\frac{1+a}{a}}{\frac{1-a}{a}}$. Simplifying further by multiplying both the numerator and the denominator by $a$, we get $\frac{1+a}{1-a}$, which matches option D.

Simplify - 1a+11a−1\frac{\frac{1}{a}+1}{\frac{1}{a}-1}a1​−1a1​+1​ A) 1−a21-a^{2}1−a2 B) 1 C) a1−a2\frac{a}{1-a^{2}}1−a2a​ D) 1+a1−a\frac{1+a}{1-a}1−a1+a​

Simplify
- $\frac{\frac{1}{a}+1}{\frac{1}{a}-1}$ A) $1-a^{2}$ B) 1
C) $\frac{a}{1-a^{2}}$ D) $\frac{1+a}{1-a}$