Add. Simplify, if possible.
-$\frac{x}{x^{2}-1}+\frac{4 x}{x-x^{2}}$
A) $\frac{-3 x-4}{(x-1)(x+1)}$
B) $\frac{-3 x^{3}+x^{2}-4 x}{\left(x^{2}-1\right)\left(x-x^{2}\right)}$
C) $\frac{-3 x+4}{(x-1)(x+1)}$
D) $\frac{-3 x^{2}-4 x}{x(x-1)(x+1)}$

Question

Quizplus · Accepted Answer

The correct answer is A because $\frac{x}{x^{2}-1}+\frac{4 x}{x-x^{2}}=\frac{x}{(x-1)(x+1)}+\frac{4 x}{x(x-1)}=\frac{x+4 x}{(x-1)(x+1)}=\frac{-3 x-4}{(x-1)(x+1)}$