Find the LCM.
-$4 a-12, a^{2}-3 a$
A) $4 a^{2}-3$
B) $4 \mathrm{a}(\mathrm{a}-3)$
C) $4 a^{2}-12$
D) $4 \mathrm{a}-3$

Question

Quizplus · Accepted Answer

The LCM of $4a-12$ and $a^2-3a$ can be found by factoring each expression and then taking the product of the highest power of common and uncommon factors. Factoring out the greatest common factor (GCF), we get $4a-12 = 4(a-3)$ and $a^2-3a = a(a-3)$. The LCM is $4a(a-3)$, which corresponds to choice B.

Find the LCM 4a−12,a2−3a4 a-12, a^{2}-3 a4a−12,a2−3a A) 4a2−34 a^{2}-34a2−3 B) 4a(a−3)4 \mathrm{a}(\mathrm{a}-3)4a(a−3)

Find the LCM $4 a-12, a^{2}-3 a$ A) $4 a^{2}-3$ B) $4 \mathrm{a}(\mathrm{a}-3)$