Solve the problem.
-A rectangular garden is three times as long as it is wide. If the area of the garden is $768 \mathrm{ft}^{2}$, find the length and width of the garden.
A) length: $45 \mathrm{ft}$; width: $15 \mathrm{ft}$
B) length: $256 \mathrm{ft}$; width: $3 \mathrm{ft}$
C) length: $48 \mathrm{ft}$; width: $16 \mathrm{ft}$
D) length: $16 \mathrm{ft}$; width: $\frac{16}{3} \mathrm{ft}$

Question

Quizplus · Accepted Answer

The area of a rectangle is given by the formula $A = l \times w$, where $l$ is the length and $w$ is the width. Given that the length is three times the width ($l = 3w$) and the area is $768 \mathrm{ft}^2$, we can set up the equation $3w \times w = 768$. Solving for $w$, we find $w = 16 \mathrm{ft}$ and $l = 48 \mathrm{ft}$, making option C correct.

Solve the Problem 768ft2768 \mathrm{ft}^{2}768ft2 , Find the Length and Width of the Garden

Solve the Problem $768 \mathrm{ft}^{2}$ , Find the Length and Width of the Garden