Factor completely.
-$2 x^{3}+18 x^{2}+5 x+45$
A) $(2 x+5)(2 x-5)(x+9)$
B) $\left(2 x^{2}-5\right)(x-9)$
C) $\left(x^{2}+5\right)(2 x+9)$
D) $\left(2 x^{2}+5\right)(x+9)$

Question

Quizplus · Accepted Answer

The polynomial can be factored by grouping: $2x^3 + 18x^2 + 5x + 45 = (2x^3 + 18x^2) + (5x + 45)$. Factoring out common terms gives $2x^2(x + 9) + 5(x + 9)$, which can be further factored as $(2x^2 + 5)(x + 9)$.

Factor Completely 2x3+18x2+5x+452 x^{3}+18 x^{2}+5 x+452x3+18x2+5x+45 A) (2x+5)(2x−5)(x+9)(2 x+5)(2 x-5)(x+9)(2x+5)(2x−5)(x+9) B) (2x2−5)(x−9)\left(2 x^{2}-5\right)(x-9)(2x2−5)(x−9)

Factor Completely $2 x^{3}+18 x^{2}+5 x+45$ A) $(2 x+5)(2 x-5)(x+9)$ B) $\left(2 x^{2}-5\right)(x-9)$