Factor completely.
-$20 x^{3}-54 x^{2}+10 x$
A) $x(2 x-5)(10 x-2)$
B) $x(4 x-10)(5 x-1)$
C) $2 x(2 x-5)(5 x-1)$
D) $2\left(2 x^{2}-5\right)(5 x-1)$

Name: Factor completely. -$20 x^{3}-54 x^{2}+10 x$ A) $x(2 x-5)(10 x-2)$ B) $x(4 x-10)(5 x-1)$ C) $2 x(2 x-5)(5 x-1)$ D) $2\left(2 x^{2}-5\right)(5 x-1)$
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Question

Quizplus · Accepted Answer

First, factor out the greatest common factor (GCF), which is $2x$, giving $2x(10x^2 - 27x + 5)$. Then, factor the quadratic inside the parentheses to get $2x(2x-5)(5x-1)$.

Factor Completely 20x3−54x2+10x20 x^{3}-54 x^{2}+10 x20x3−54x2+10x A) x(2x−5)(10x−2)x(2 x-5)(10 x-2)x(2x−5)(10x−2) B) x(4x−10)(5x−1)x(4 x-10)(5 x-1)x(4x−10)(5x−1)

Factor Completely $20 x^{3}-54 x^{2}+10 x$ A) $x(2 x-5)(10 x-2)$ B) $x(4 x-10)(5 x-1)$