Factor completely.
-$50 x^{2}-98 y^{2}$
A) $(5 x-7 y)(10 x+14 y)$
B) $(10 x-14 y)(5 x+7 y)$
C) $2(5 x-7 y)(5 x+7 y)$
D) $2(5 x+7 y)^{2}$

Question

Quizplus · Accepted Answer

This expression is a difference of squares, which can be factored as $a^2 - b^2 = (a - b)(a + b)$. Factoring out the greatest common factor (GCF) of 2 first gives $2(25x^2 - 49y^2)$, which then factors further into $2(5x - 7y)(5x + 7y)$.

Factor Completely 50x2−98y250 x^{2}-98 y^{2}50x2−98y2 A) (5x−7y)(10x+14y)(5 x-7 y)(10 x+14 y)(5x−7y)(10x+14y) B) (10x−14y)(5x+7y)(10 x-14 y)(5 x+7 y)(10x−14y)(5x+7y)

Factor Completely $50 x^{2}-98 y^{2}$ A) $(5 x-7 y)(10 x+14 y)$ B) $(10 x-14 y)(5 x+7 y)$