Factor using the ac-method.
-$9 x^{4}+12 x^{2}+4$
A) $\left(3 x^{2}+2\right)\left(3 x^{2}+2\right)$
B) $\left(3 x^{2}+1\right)\left(3 x^{2}+4\right)$
C) $\left(9 x^{2}+2\right)\left(x^{2}+2\right)$
D) $\left(3 x^{2}-2\right)\left(3 x^{2}-2\right)$

Question

Quizplus · Accepted Answer

The given expression is a perfect square trinomial, factoring to $(3x^2 + 2)^2$, because $9x^4$ is the square of $3x^2$, $4$ is the square of $2$, and $12x^2$ is twice the product of $3x^2$ and $2$.

Factor Using the Ac-Method 9x4+12x2+49 x^{4}+12 x^{2}+49x4+12x2+4 A) (3x2+2)(3x2+2)\left(3 x^{2}+2\right)\left(3 x^{2}+2\right)(3x2+2)(3x2+2) B) (3x2+1)(3x2+4)\left(3 x^{2}+1\right)\left(3 x^{2}+4\right)(3x2+1)(3x2+4)

Factor Using the Ac-Method $9 x^{4}+12 x^{2}+4$ A) $\left(3 x^{2}+2\right)\left(3 x^{2}+2\right)$ B) $\left(3 x^{2}+1\right)\left(3 x^{2}+4\right)$