Factor using the ac-method.
-$6 x^{2}+17 x+12$
A) $(3 x-4)(2 x-3)$
B) $(6 x+4)(x+3)$
C) prime
D) $(3 x+4)(2 x+3)$

Question

Quizplus · Accepted Answer

The ac-method involves multiplying 'a' and 'c' (from ax^2 + bx + c) which gives 6*12=72. We look for two numbers that multiply to 72 and add to 17 (the 'b' value), which are 9 and 8. Splitting the middle term 17x into 9x and 8x and factoring by grouping gives us (3x+4)(2x+3).

Factor Using the Ac-Method 6x2+17x+126 x^{2}+17 x+126x2+17x+12 A) (3x−4)(2x−3)(3 x-4)(2 x-3)(3x−4)(2x−3) B) (6x+4)(x+3)(6 x+4)(x+3)(6x+4)(x+3)

Factor Using the Ac-Method $6 x^{2}+17 x+12$ A) $(3 x-4)(2 x-3)$ B) $(6 x+4)(x+3)$