Factor.
-$12 z^{3}+7 z^{2}-12 z$
A) $\left(z^{2}-3\right)(12 z+4)$
B) $(3 z-4)(4 z+3)$
C) $z(3 z+4)(4 z-3)$
D) $z(12 z+1)(z-12)$

Name: Factor. -$12 z^{3}+7 z^{2}-12 z$ A) $\left(z^{2}-3\right)(12 z+4)$ B) $(3 z-4)(4 z+3)$ C) $z(3 z+4)(4 z-3)$ D) $z(12 z+1)(z-12)$
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Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $z$, giving $z(12z^2 + 7z - 12)$. Then, factor the quadratic expression inside the parentheses to get $z(3z + 4)(4z - 3)$.

Factor - 12z3+7z2−12z12 z^{3}+7 z^{2}-12 z12z3+7z2−12z A) (z2−3)(12z+4)\left(z^{2}-3\right)(12 z+4)(z2−3)(12z+4) B) (3z−4)(4z+3)(3 z-4)(4 z+3)(3z−4)(4z+3)

Factor
- $12 z^{3}+7 z^{2}-12 z$ A) $\left(z^{2}-3\right)(12 z+4)$ B) $(3 z-4)(4 z+3)$