Multiply.
-$(p+9 q)(p-9 q)$
A) $p^{2}-18 p q-81 q^{2}$
B) $p^{2}-18 q^{2}$
C) $p^{2}+18 p q-81 q^{2}$
D) $p^{2}-81 q^{2}$

Name: Multiply. -$(p+9 q)(p-9 q)$ A) $p^{2}-18 p q-81 q^{2}$ B) $p^{2}-18 q^{2}$ C) $p^{2}+18 p q-81 q^{2}$ D) $p^{2}-81 q^{2}$
Brand: Quizplus
Rating: 4.8 (39 reviews)

Question

Quizplus · Accepted Answer

This is an application of the difference of squares formula, $a^2 - b^2 = (a+b)(a-b)$, where $a = p$ and $b = 9q$. So, $(p+9q)(p-9q) = p^2 - (9q)^2 = p^2 - 81q^2$.

Multiply - (p+9q)(p−9q)(p+9 q)(p-9 q)(p+9q)(p−9q) A) p2−18pq−81q2p^{2}-18 p q-81 q^{2}p2−18pq−81q2 B) p2−18q2p^{2}-18 q^{2}p2−18q2

Multiply
- $(p+9 q)(p-9 q)$ A) $p^{2}-18 p q-81 q^{2}$ B) $p^{2}-18 q^{2}$