Multiply.
-$\left(\mathrm{c}+\frac{5}{3}\right)^{2}$
A) $c^{2}+\frac{10}{3}$
B) $c^{2}+\frac{10}{3} c+\frac{25}{9}$
C) $c^{2}+\frac{25}{9}$
D) $2 c+\frac{10}{3} c+\frac{10}{3}$

Question

Quizplus · Accepted Answer

To square the binomial $\left(c+\frac{5}{3}\right)^{2}$, apply the formula $(a+b)^2 = a^2 + 2ab + b^2$. Here, $a=c$ and $b=\frac{5}{3}$, so it becomes $c^2 + 2\left(c\cdot\frac{5}{3}\right) + \left(\frac{5}{3}\right)^2 = c^2 + \frac{10}{3}c + \frac{25}{9}$.

Multiply - (c+53)2\left(\mathrm{c}+\frac{5}{3}\right)^{2}(c+35​)2 A) c2+103c^{2}+\frac{10}{3}c2+310​ B) c2+103c+259c^{2}+\frac{10}{3} c+\frac{25}{9}c2+310​c+925​ C) c2+259c^{2}+\frac{25}{9}c2+925​ D) 2c+103c+1032 c+\frac{10}{3} c+\frac{10}{3}2c+310​c+310​

Multiply
- $\left(\mathrm{c}+\frac{5}{3}\right)^{2}$ A) $c^{2}+\frac{10}{3}$ B) $c^{2}+\frac{10}{3} c+\frac{25}{9}$ C) $c^{2}+\frac{25}{9}$ D) $2 c+\frac{10}{3} c+\frac{10}{3}$