Multiply.
-$(x-5)(x-8)$
A) $x^{2}-13 x+40$
B) $x^{2}-13 x-13$
C) $x-13 x+40$
D) $x^{2}-16 x+40$

Name: Multiply. -$(x-5)(x-8)$ A) $x^{2}-13 x+40$ B) $x^{2}-13 x-13$ C) $x-13 x+40$ D) $x^{2}-16 x+40$
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Question

Quizplus · Accepted Answer

Using the distributive property (FOIL method) to multiply the two binomials: First terms ($x \cdot x = x^2$), Outer terms ($x \cdot -8 = -8x$), Inner terms ($-5 \cdot x = -5x$), and Last terms ($-5 \cdot -8 = 40$). Adding these together gives $x^2 - 13x + 40$.

Multiply - (x−5)(x−8)(x-5)(x-8)(x−5)(x−8) A) x2−13x+40x^{2}-13 x+40x2−13x+40 B) x2−13x−13x^{2}-13 x-13x2−13x−13 C) x−13x+40x-13 x+40x−13x+40 D) x2−16x+40x^{2}-16 x+40x2−16x+40

Multiply
- $(x-5)(x-8)$ A) $x^{2}-13 x+40$ B) $x^{2}-13 x-13$ C) $x-13 x+40$ D) $x^{2}-16 x+40$