Find a parameterization of the curve $\frac{(x-2)^{2}}{25}+\frac{(y-3)^{2}}{16}=1$ so that the curve is traversed in a counter-clockwise direction starting at $(7,3)$.

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The Answer of Find a parameterization of the curve $\frac{(x-2)^{2}}{25}+\frac{(y-3)^{2}}{16}=1$ so that the curve is traversed in a counter-clockwise direction starting at $(7,3)$.

Find a Parameterization of the Curve (x−2)225+(y−3)216=1\frac{(x-2)^{2}}{25}+\frac{(y-3)^{2}}{16}=125(x−2)2​+16(y−3)2​=1 So That the Curve Is Traversed in a Counter-Clockwise Direction

Find a Parameterization of the Curve $\frac{(x-2)^{2}}{25}+\frac{(y-3)^{2}}{16}=1$ So That the Curve Is Traversed in a Counter-Clockwise Direction