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(x−4)2+(y+3)2=16(x-4)^{2}+(y+3)^{2}=16 Is a Circle of Radius 4 Centered At (−4,3)(-4,3)

Question 40

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(x−4)2+(y+3)2=16(x-4)^{2}+(y+3)^{2}=16 is a circle of radius 4 centered at (−4,3)(-4,3)

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