If the circle $x^{2}+y^{2}+14 x-6 y+9=0$ is converted to the parametric equations $x=h+r \cos t, y=k+r \sin t, 0 \leq t \leq 2 \pi$, then h=------------,k=----------,and r=------------.

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The Answer of If the circle $x^{2}+y^{2}+14 x-6 y+9=0$ is converted to the parametric equations $x=h+r \cos t, y=k+r \sin t, 0 \leq t \leq 2 \pi$, then h=------------,k=----------,and r=------------.

If the Circle x2+y2+14x−6y+9=0x^{2}+y^{2}+14 x-6 y+9=0x2+y2+14x−6y+9=0 Is Converted to the Parametric Equations

If the Circle $x^{2}+y^{2}+14 x-6 y+9=0$ Is Converted to the Parametric Equations