A sequence $a_{n}$ can be defined by a recurrence relation, which gives the first term, $a_{1}$, and a formula for finding $a_{n}$ in terms of the previous term, $a_{n-1}$. For the recurrence relation below, what is the formula for the general term?
$a_{1}=1 ; a_{n}=\frac{a_{n-1}}{9}$
A) $a_{n}=\left(\frac{1}{9}\right)^{n}$
B) $a_{n}=\left(\frac{1}{9}\right)^{n-1}$
C) $a_{n}=\frac{1}{9 n}$
D) $a_{n}=\frac{1}{9(n-1)}$

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The Answer of A sequence $a_{n}$ can be defined by a recurrence relation, which gives the first term, $a_{1}$, and a formula for finding $a_{n}$ in terms of the previous term, $a_{n-1}$. For the recurrence relation below, what is the formula for the general term?
$a_{1}=1 ; a_{n}=\frac{a_{n-1}}{9}$
A) $a_{n}=\left(\frac{1}{9}\right)^{n}$
B) $a_{n}=\left(\frac{1}{9}\right)^{n-1}$
C) $a_{n}=\frac{1}{9 n}$
D) $a_{n}=\frac{1}{9(n-1)}$

A Sequence ana_{n}an​ Can Be Defined by a Recurrence Relation, Which Gives the Which

A Sequence $a_{n}$ Can Be Defined by a Recurrence Relation, Which Gives the Which