The functions $f$ and $F$ are given by $f(x)=k x^{p}$ and $F(x)=\sqrt{\frac{k x^{p-1}}{p}}$.
Suppose $f(x)=\frac{x^{9}}{8}$. What must $F$ be?

Name: The functions $f$ and $F$ are given by $f(x)=k x^{p}$ and $F(x)=\sqrt{\frac{k x^{p-1}}{p}}$. Suppose $f(x)=\frac{x^{9}}{8}$. What must $F$ be?
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The Answer of The functions $f$ and $F$ are given by $f(x)=k x^{p}$ and $F(x)=\sqrt{\frac{k x^{p-1}}{p}}$.
Suppose $f(x)=\frac{x^{9}}{8}$. What must $F$ be?

The Functions fff And FFF Are Given By f(x)=kxpf(x)=k x^{p}f(x)=kxp And F(x)=kxp−1pF(x)=\sqrt{\frac{k x^{p-1}}{p}}F(x)=pkxp−1​​ Suppose

The Functions $f$ And $F$ Are Given By $f(x)=k x^{p}$ And $F(x)=\sqrt{\frac{k x^{p-1}}{p}}$
Suppose