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Given f−1(x)=800(1.05)xf^{-1}(x)=800(1.05)^{x} , Solve f−1(x)=1000f^{-1}(x)=1000 Round to 3 Decimal Places

Question 37

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Given f−1(x)=800(1.05)xf^{-1}(x)=800(1.05)^{x} , solve f−1(x)=1000f^{-1}(x)=1000 . Round to 3 decimal places.

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