Write $\frac{3 \sin (x-3)}{4 \cos (x-3)}$ in terms of the tangent function.
A) $\frac{3}{4} \tan (x-3)$
B) $3 \tan (x-3)$
C) $\frac{3}{4} \cdot \frac{\tan (x-3)}{x-3}$
D) $\frac{3}{4 \tan (x-3)}$

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The Answer of Write $\frac{3 \sin (x-3)}{4 \cos (x-3)}$ in terms of the tangent function.
A) $\frac{3}{4} \tan (x-3)$
B) $3 \tan (x-3)$
C) $\frac{3}{4} \cdot \frac{\tan (x-3)}{x-3}$
D) $\frac{3}{4 \tan (x-3)}$

Write 3sin⁡(x−3)4cos⁡(x−3)\frac{3 \sin (x-3)}{4 \cos (x-3)}4cos(x−3)3sin(x−3)​ In Terms of the Tangent Function

Write $\frac{3 \sin (x-3)}{4 \cos (x-3)}$ In Terms of the Tangent Function