The following figure shows the graphs of
(A). $y=e^{-x}$ (
B). $y=10^{-x}$ (
C). $ y=\ln (-x)$ (
D). $y=\log (-x)$. Which one is the graph of A?

Name: The following figure shows the graphs of (A). $y=e^{-x}$ ( B). $y=10^{-x}$ ( C). $ y=\ln (-x)$ ( D). $y=\log (-x)$. Which one is the graph of A?
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Question

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The Answer of The following figure shows the graphs of
(A). $y=e^{-x}$ (
B). $y=10^{-x}$ (
C). $ y=\ln (-x)$ (
D). $y=\log (-x)$. Which one is the graph of A?

The Following Figure Shows the Graphs of (A) y=e−xy=e^{-x}y=e−x (B) y=10−xy=10^{-x}y=10−x (C) y=ln⁡(−x) y=\ln (-x)y=ln(−x)

The Following Figure Shows the Graphs of
(A) $y=e^{-x}$ (B) $y=10^{-x}$ (C) $y=\ln (-x)$