Rewriting the statement $\ln \left(\frac{1}{8}\right)=-2.079$ using exponents gives
A) $e^{-2.079}=\frac{1}{8}$
B) $e^{-2.079}=8$
C) $e^{8}=\frac{1}{-2.079}$
D) $e^{8}=-2.079$

Question

Quizplus · Accepted Answer

The natural logarithm $\ln(x)$ is the power to which $e$ must be raised to get $x$. Therefore, $\ln \left(\frac{1}{8}\right)=-2.079$ means $e^{-2.079}=\frac{1}{8}$.

Rewriting the Statement ln⁡(18)=−2.079\ln \left(\frac{1}{8}\right)=-2.079ln(81​)=−2.079 Using Exponents Gives A) e−2.079=18e^{-2.079}=\frac{1}{8}e−2.079=81​ B) e−2.079=8e^{-2.079}=8e−2.079=8 C) e8=1−2.079e^{8}=\frac{1}{-2.079}e8=−2.0791​

Rewriting the Statement $\ln \left(\frac{1}{8}\right)=-2.079$ Using Exponents Gives
A) $e^{-2.079}=\frac{1}{8}$ B) $e^{-2.079}=8$ C) $e^{8}=\frac{1}{-2.079}$