Suppose $g(x)=\frac{1-11 x}{3}$ and suppose that $f$ is an invertible function such that
$f^{-1}(x)=3(x-5)$. Find $f(g(x))$ and
write it in the form $a x+b$.

Name: Suppose $g(x)=\frac{1-11 x}{3}$ and suppose that $f$ is an invertible function such that $f^{-1}(x)=3(x-5)$. Find $f(g(x))$ and write it in the form $a x+b$.
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The Answer of Suppose $g(x)=\frac{1-11 x}{3}$ and suppose that $f$ is an invertible function such that
$f^{-1}(x)=3(x-5)$. Find $f(g(x))$ and
write it in the form $a x+b$.

Suppose g(x)=1−11x3g(x)=\frac{1-11 x}{3}g(x)=31−11x​ And Suppose That fff Is an Invertible Function Such That

Suppose $g(x)=\frac{1-11 x}{3}$ And Suppose That $f$ Is an Invertible Function Such That