Find the foci of the ellipse. Round to the nearest tenth if necessary.
-$\frac{x^{2}}{289}+\frac{y^{2}}{64}=1$
A) $(-19,0),(19,0)$
B) $(-15,0),(15,0)$
C) $(-17,0),(17,0)$
D) $(-13,0),(13,0)$

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The Answer of Find the foci of the ellipse. Round to the nearest tenth if necessary.
-$\frac{x^{2}}{289}+\frac{y^{2}}{64}=1$
A) $(-19,0),(19,0)$
B) $(-15,0),(15,0)$
C) $(-17,0),(17,0)$
D) $(-13,0),(13,0)$

Find the Foci of the Ellipse x2289+y264=1\frac{x^{2}}{289}+\frac{y^{2}}{64}=1289x2​+64y2​=1 A) (−19,0),(19,0)(-19,0),(19,0)(−19,0),(19,0) B) (−15,0),(15,0)(-15,0),(15,0)(−15,0),(15,0) C) (−17,0),(17,0)(-17,0),(17,0)(−17,0),(17,0) D) (−13,0),(13,0)(-13,0),(13,0)(−13,0),(13,0)

Find the Foci of the Ellipse $\frac{x^{2}}{289}+\frac{y^{2}}{64}=1$ A) $(-19,0),(19,0)$ B) $(-15,0),(15,0)$ C) $(-17,0),(17,0)$ D) $(-13,0),(13,0)$