Find an equation of the circle with the given center and radius.
-Center (0, - 6), radius 2
A) $x^{2}+(y-6)^{2}=2$
B) $(x+6)^{2}+y^{2}=4$
C) $x^{2}+(y+6)^{2}=4$
D) $(x-6)^{2}+y^{2}=4$

Question

Quizplus · Accepted Answer

The general equation for a circle with center $(h, k)$ and radius $r$ is $(x-h)^{2}+(y-k)^{2}=r^{2}$. Substituting $h=0$, $k=-6$, and $r=2$ into this formula gives $x^{2}+(y+6)^{2}=4$.

Find an Equation of the Circle with the Given Center x2+(y−6)2=2x^{2}+(y-6)^{2}=2x2+(y−6)2=2

Find an Equation of the Circle with the Given Center $x^{2}+(y-6)^{2}=2$