Solve the problem.
-Arches in the shapes of parabolas are often used in construction. Find the equation of a parabolic arc that is 20 feet high at its highest point and 28 feet wide at the base, as illustrated in the figure. Place the origin at the midpoint of the base.

A) $y=-x^{2}+28$
B) $y=\frac{5}{49} x^{2}+20$
C) $y=-x^{2}+20$
D) $y=-\frac{5}{49} x^{2}+20$

Question

Solve the problem.
-Arches in the shapes of parabolas are often used in construction. Find the equation of a parabolic arc that is 20 feet high at its highest point and 28 feet wide at the base, as illustrated in the figure. Place the origin at the midpoint of the base.

A) $y=-x^{2}+28$ 
B) $y=\frac{5}{49} x^{2}+20$ 
C) $y=-x^{2}+20$ 
D) $y=-\frac{5}{49} x^{2}+20$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Arches in the shapes of parabolas are often used in construction. Find the equation of a parabolic arc that is 20 feet high at its highest point and 28 feet wide at the base, as illustrated in the figure. Place the origin at the midpoint of the base.

A) $y=-x^{2}+28$ 
B) $y=\frac{5}{49} x^{2}+20$ 
C) $y=-x^{2}+20$ 
D) $y=-\frac{5}{49} x^{2}+20$

Solve the Problem y=−x2+28y=-x^{2}+28y=−x2+28 B) y=549x2+20y=\frac{5}{49} x^{2}+20y=495​x2+20 C) y=−x2+20y=-x^{2}+20y=−x2+20 D) y=−549x2+20y=-\frac{5}{49} x^{2}+20y=−495​x2+20

Solve the Problem $y=-x^{2}+28$ B) $y=\frac{5}{49} x^{2}+20$ C) $y=-x^{2}+20$ D) $y=-\frac{5}{49} x^{2}+20$