Solve.
-$\log _{2}(2 x+8)=\log _{2}(2 x+3)$
A) $\{5\}$
B) $\{0\}$
C) $\{2\}$
D) $\varnothing$

Name: Solve. -$\log _{2}(2 x+8)=\log _{2}(2 x+3)$ A) $\{5\}$ B) $\{0\}$ C) $\{2\}$ D) $\varnothing$
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Question

Quizplus · Accepted Answer

Since the bases of the logarithms are the same, we can equate the arguments: $2x + 8 = 2x + 3$. Subtracting $2x$ from both sides gives $8 = 3$, which is a contradiction. Therefore, there is no solution to the equation.

Solve - log⁡2(2x+8)=log⁡2(2x+3)\log _{2}(2 x+8)=\log _{2}(2 x+3)log2​(2x+8)=log2​(2x+3) A) {5}\{5\}{5} B) {0}\{0\}{0} C) {2}\{2\}{2} D) ∅\varnothing∅

Solve
- $\log _{2}(2 x+8)=\log _{2}(2 x+3)$ A) $\{5\}$ B) $\{0\}$ C) $\{2\}$ D) $\varnothing$