A city is growing at the rate of $0.8 \%$ annually. If there were $5,316,000$ residents in the city in 1995 , find how many (to the nearest ten- thousand) were living in that city in 2000 . Use $\mathrm{y}=5,316,000(2.7)^{0.008 t}$
A) $14,350,000$
B) $5,560,000$
C) 570,000
D) $5,530,000$

Question

Quizplus · Accepted Answer

The city is growing at the rate of $0.8 \%$ annually, so the growth factor is $1.008$. The number of residents in the city in 2000 is:$$y = 5,316,000(1.008)^{0.008(5)} \approx 5,530,000$$To the nearest ten-thousand, the number of residents in the city in 2000 is $5,530,000$.

A City Is Growing at the Rate Of 0.8%0.8 \%0.8% Annually If There Were

A City Is Growing at the Rate Of $0.8 \%$ Annually If There Were