Solve the equation by completing the square
-$\mathrm{x}^{2}+5 \mathrm{x}-5=0$
A) $\left\{\frac{-5-3 \sqrt{5}}{2}\right\}$

B) $\left\{\frac{-5 \pm 3 \sqrt{5}}{2}\right\}$

C) $\left\{\frac{5+3 \sqrt{5}}{2}\right\}$

D) $\{-5 \pm 3 \sqrt{5}\}$

Question

Solve the equation by completing the square
-$\mathrm{x}^{2}+5 \mathrm{x}-5=0$
A) $\left\{\frac{-5-3 \sqrt{5}}{2}\right\}$

B) $\left\{\frac{-5 \pm 3 \sqrt{5}}{2}\right\}$

C) $\left\{\frac{5+3 \sqrt{5}}{2}\right\}$

D) $\{-5 \pm 3 \sqrt{5}\}$

Quizplus · Accepted Answer

To solve the equation $x^2 + 5x - 5 = 0$ by completing the square, first move the constant term to the other side: $x^2 + 5x = 5$. Then, add $\left(\frac{5}{2}\right)^2 = \frac{25}{4}$ to both sides to complete the square: $x^2 + 5x + \frac{25}{4} = 5 + \frac{25}{4} = \frac{45}{4}$. This gives $\left(x + \frac{5}{2}\right)^2 = \frac{45}{4}$. Taking the square root of both sides gives $x + \frac{5}{2} = \pm \sqrt{\frac{45}{4}}$, which simplifies to $x = -\frac{5}{2} \pm \frac{3\sqrt{5}}{2}$, or $\frac{-5 \pm 3 \sqrt{5}}{2}$.

Solve the Equation by Completing the Square - x2+5x−5=0\mathrm{x}^{2}+5 \mathrm{x}-5=0x2+5x−5=0 A) {−5−352}\left\{\frac{-5-3 \sqrt{5}}{2}\right\}{2−5−35​​}

Solve the Equation by Completing the Square
- $\mathrm{x}^{2}+5 \mathrm{x}-5=0$ A) $\left\{\frac{-5-3 \sqrt{5}}{2}\right\}$