A student tries to solve $\sqrt{\mathrm{x}+7}=\sqrt{\mathrm{x}}+4$ by squaring both sides and gets $\mathrm{x}+7=\mathrm{x}+16$.
Why is this not correct?

Name: A student tries to solve $\sqrt{\mathrm{x}+7}=\sqrt{\mathrm{x}}+4$ by squaring both sides and gets $\mathrm{x}+7=\mathrm{x}+16$. Why is this not correct?
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The Answer of A student tries to solve $\sqrt{\mathrm{x}+7}=\sqrt{\mathrm{x}}+4$ by squaring both sides and gets $\mathrm{x}+7=\mathrm{x}+16$.
Why is this not correct?

A Student Tries to Solve x+7=x+4\sqrt{\mathrm{x}+7}=\sqrt{\mathrm{x}}+4x+7​=x​+4 By Squaring Both Sides and Gets

A Student Tries to Solve $\sqrt{\mathrm{x}+7}=\sqrt{\mathrm{x}}+4$ By Squaring Both Sides and Gets