Solve for the specified variable
-$\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$ for $c$

A) $c=a b(a+b)$

B) $c=a+b$

C) $c=\frac{a+b}{a b}$

D) $c=\frac{a b}{a+b}$

Question

Solve for the specified variable
-$\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$ for $c$

A) $c=a b(a+b)$

B) $c=a+b$

C) $c=\frac{a+b}{a b}$

D) $c=\frac{a b}{a+b}$

Quizplus · Accepted Answer

To solve for $c$, you start with $\frac{1}{a}+\frac{1}{b}=\frac{1}{c}$. Finding a common denominator for the left side gives $\frac{a+b}{ab}=\frac{1}{c}$. Inverting both sides to solve for $c$ gives $c=\frac{ab}{a+b}$.

Solve for the Specified Variable - 1a+1b=1C\frac{1}{a}+\frac{1}{b}=\frac{1}{C}a1​+b1​=C1​ For ccc A) c=ab(a+b)c=a b(a+b)c=ab(a+b) B) c=a+bc=a+bc=a+b

Solve for the Specified Variable
- $\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$ For $c$ A) $c=a b(a+b)$ B) $c=a+b$